The 6-number sequence as it stands

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Waz
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Post by Waz »

re-phaelam-ed wrote:
Waz wrote:
BunnyRabbit wrote:
You can brute force a crib to unlock the whole thing if you can guess one thing that is in the plain text and have an idea that the technique used isn't based on a random pad.
You're talking about something different (attacks on large datasets encrypted with smaller keys). We're talking about one-time pads here, which done correctly mean that you can't reduce your guesses. Try every possible combination and all you'll get is every possible six-letter string.
was just thinking...lets say someone guesses the 6th num. it probably wont do anything till they enable whatever it is supposed to reveal. everything is probably timed. the release date is set. that wont change. it will either be the release date...or we'll be sitting with 6 nums till they let us know what its for.
Probably. It's only six digits long. If we knew what to do with the numbers, we could have a computer run through the possible missing number combinations in a fraction of a second and get our answer.

But we don't. I really think this information is meaningless until we get a numbers station pad to decrypt them with (which is why I don't find this all that interesting... it's just a collection game really. "Watch all of our ads!" instead of "do something clever with these clues").

I mean, hopefully we're just all too stupid to have seen what the clever thing is, but I'm betting on it being a "collect the numbers and then collect the key" thing :-(

I don't really see this as something that comes right out of the minds of Mike and Marcus, either. Seems like a ad agency stunt to me.

It's kinda fun, but it's starting to smell more of marketing than intrigue.
Last edited by Waz on Sun Apr 28, 2013 11:48 pm, edited 1 time in total.
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re-phaelam-ed
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Post by re-phaelam-ed »

tried something on the first num...
6/9/9/7/4/2 = 0.00132275132275

132275

:)
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re-phaelam-ed
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Post by re-phaelam-ed »

re-phaelam-ed wrote:tried something on the first num...
6/9/9/7/4/2 = 0.00132275132275

132275

:)
k i was just f-ing around...but i divided each first number but the first number of the next set and got...
6/6/7/9/5 = 0.00317460317460

317460

:|
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re-phaelam-ed
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Post by re-phaelam-ed »

re-phaelam-ed wrote:
re-phaelam-ed wrote:tried something on the first num...
6/9/9/7/4/2 = 0.00132275132275

132275

:)
k i was just f-ing around...but i divided each first number but the first number of the next set and got...
6/6/7/9/5 = 0.00317460317460

317460

:|
ummmm...all the last numbers
2/5/8/7/5 = 0.00142857142857

142857
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tubolcane
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Post by tubolcane »

!!!FNORD!!!
place the numbers at the top of this page in a list going down, one number on each line. each goes beneath the previous one. put that list next to this one, with the following new numbers ordered the same way (top to bottom): 667925 921341 987679 732592 412592 258765

not good at maths, but the 2592's seem to want to mate somehow. and there are FOUR of them.. order the list so 2592 stands out going top to bottom in the old numbers, left to right in these new numbers. this would seem to confirm all the numbers, at the least, provided we are right. i am having a very hard time getting this message out. copy as you will.

heading out soon.
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Roo
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Post by Roo »

Look away from the internet for a week and... how many nights and weird mornings has this shit been going on !?
Waz
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Post by Waz »

Solved it, everybody. Actually pretty simple!

Each number has a corresponding pair generated using transcyclic group reduction.

So we get:

699742 / 628315 / 717228 / 936557 / ------ / 519225
699723 / 628303 / 717207 / 936537 / ------ / 519200

Subtract the bottom row from the top row and:

19 12 21 20 -- 25

Each number corresponds to its letter in the alphabet (1 = a, 2 = b, etc.), and there's your answer.

And of course, the missing number is an Abelian pair, so we can predict that it's 632476 (with the corresponding transcyclic code 632456). That leaves us with the fully-deciphered text:

19 12 21 20 20 25
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Post by Integer »

Ken Cosgrove wrote:New code found on a pub jukebox in Southern England, embedded within another song.







:wink:
haha brilliant. I love how the code comes in right after "give me a sign"... :wink:
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Post by Hexahedral »

Waz wrote:Solved it, everybody. Actually pretty simple!

Each number has a corresponding pair generated using transcyclic group reduction.

So we get:

699742 / 628315 / 717228 / 936557 / ------ / 519225
699723 / 628303 / 717207 / 936537 / ------ / 519200

Subtract the bottom row from the top row and:

19 12 21 20 -- 25

Each number corresponds to its letter in the alphabet (1 = a, 2 = b, etc.), and there's your answer.

And of course, the missing number is an Abelian pair, so we can predict that it's 632476 (with the corresponding transcyclic code 632456). That leaves us with the fully-deciphered text:

19 12 21 20 20 25
19/12/21/20/20/25
=
S/L/U/T/T/Y
=
OMGLOL
Last edited by Hexahedral on Mon Apr 29, 2013 12:23 am, edited 1 time in total.
ilzmastr
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Post by ilzmastr »

Waz wrote:Solved it, everybody. Actually pretty simple!

Each number has a corresponding pair generated using transcyclic group reduction.

So we get:

699742 / 628315 / 717228 / 936557 / ------ / 519225
699723 / 628303 / 717207 / 936537 / ------ / 519200

Subtract the bottom row from the top row and:

19 12 21 20 -- 25

Each number corresponds to its letter in the alphabet (1 = a, 2 = b, etc.), and there's your answer.

And of course, the missing number is an Abelian pair, so we can predict that it's 632476 (with the corresponding transcyclic code 632456). That leaves us with the fully-deciphered text:

19 12 21 20 20 25
since people might wonder:
19 12 21 20 20 25 = slutty (via alphabet conversion)
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Post by ilzmastr »

duk_koo_kim wrote:
ilzmastr wrote:After sufficient testing, my results indicate that it is highly unlikely that BoC are reusing a 3 member OTP on the 36 digit code (unlikely and not impossible, since the 36 digit code is not completely known yet). the most legible results of my brute force crack are here:


What I did:
Basically I assumed that every 2 digits of the 36 digit code constituted 1 member of the final message (to represent every letter of the alphabet with a number in you have to use at least 2 digits), and I tried all combinations of 3 member pads (00,00,00 to 26,26,26 [no more is needed, bunch of redundancy if you do until 99,99,99]) repeating throughout the BoC code, and then searched the fragments of each of those outputs against the Oxford dictionary and a little BoC list.
(for the unknown 5th BoC code portion i just assumed 01,01,01 - so I tested: [69,97,42,62,83,15,71,72,28,93,65,57,01,01,01,51,92,25])
cool shit! (if somewhat inconclusive...) how long did this take to compute?

"foxyawhpjdimpwinjg" looks like something my sister and I used to type into the text-to-speech program on our first computer (ca. 1992) in one of our many attempts to break it...
believe it or not, running my python script only took 10 seconds! (hash tables have very fast access)
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Post by ilzmastr »

Waz wrote:Not sure if I've missed something about what you're trying to rule out ilzmastr, but the point of a (properly-done) message encrypted with a one-time-pad is that you couldn't rule out the decryption keys, because the pad/key will be long enough that your guesses would produce EVERY possible message. You could run through every possible decryption, and you'd find the messages "MILEY C", "BIEBER", "COFFEE" and "DEMONS" in your output. The point is that without the correct pad, you wouldn't know which one is the message you're after.
yea, if there is no repetition of a pad, then yes, you have no chance of decrypting. I was just reading about the venona project where Russian communications were compromised by a US lieutenant who realized that the Russians were being lazy and reusing pads.

The reason I tried this is because by failing to find a re-usable pad (although it could be any length, not just 3 characters/numbers) I prove that BoC will have to provide a key to their code, or at least that there is some key floating around somewhere. (and yes, I've tried keys specific to the 6 digit sub-codes like record, vinyl, bbc1... etc)
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Post by Douay-Rheims »

i've been plugging these codes into my Enigma machine all evening all all I get is "New Album in June"
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In_The_Annexe
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Post by In_The_Annexe »

Douay-Rheims wrote:i've been plugging these codes into my Enigma machine all evening all all I get is "New Album in June"
this is old speculation but heck, if I only had to wait until then I would be pretty damn happy.
you don't care to hear until you listen
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Post by ilzmastr »

Waz wrote:I'm betting on it being a "collect the numbers and then collect the key" thing
Yes, I am expecting the same.
But this is still a super fun addicting game!
detroit lofi
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Post by detroit lofi »

Someone on Facebook said the final numbers were just aired on BBC 6 music. Any word of that?
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Post by Vostok »

detroit lofi wrote:Someone on Facebook said the final numbers were just aired on BBC 6 music. Any word of that?
519225 was played on BBC6 like 8 hours ago
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Post by detroit lofi »

Vostok wrote:
detroit lofi wrote:Someone on Facebook said the final numbers were just aired on BBC 6 music. Any word of that?
519225 was played on BBC6 like 8 hours ago
I'm so behind... Thank you!
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Post by diabolous616 »

Mexicola wrote:
dredd1971 wrote:What is the significance and reason the codes were shown to us in the order they did xxxxxx/xxxxxx/xxxxxx/XXXXXX/xxxxxx/xxxxxx and so on............That is a big thing overlooked
That's an excellent point actually.
really think this maybe something we've overlooked :?
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Post by Waz »

That seems like too much detail to me :-) And could they even be sure the codes were found in the order they wanted? Somebody might not have found that record until yesterday, for example.
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